Answer
$n^2+7n+12$
Work Step by Step
Since,we have $\dfrac{(n+4)!}{(n+2)!}$
Thus,
$\dfrac{(n+4)!}{(n+2)!}=\dfrac{n+4 \cdot n+3 \cdot n+2 !}{n+2!}$
or, $=(n+4)(n+3)$
or, $=n^2+7n+12$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 831: 90
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