Answer
$a_n=\dfrac{(n+1)^2}{n}$;$n=1,2,3,4,...$
Work Step by Step
Since, we have $4,\dfrac{9}{2},\dfrac{16}{3},\dfrac{25}{4}...$
or,$\dfrac{4}{1},\dfrac{9}{2},\dfrac{16}{3},\dfrac{25}{4}...$
The n-the term can be represented as:
$a_n=\dfrac{(n+1)^2}{n}$;$n=1,2,3,4,...$
