Answer
{$(-2,3),(\dfrac{12}{5},-\dfrac{29}{5})$}
Work Step by Step
Re-write the first equation as: $y=-2x-1$
First equation yields: $x^2+(-2x-1)^2+3(-2x-1)=22$ or, $5x^2--2x-24=0$
or,$(5x-2)(x+2)=0$
or, $x=${$-2,\dfrac{12}{5}$}
From second equation $2x+y=-1$ when $x=-2$, we have $y=3$
From second equation $2x+y=-1$ when $x=\dfrac{12}{5}$, we have $y=-\dfrac{29}{5}$
Thus, solution set is: {$(-2,3),(\dfrac{12}{5},-\dfrac{29}{5})$}
