Answer
$(x,y)=${$(0,1),(1,2)$}
Work Step by Step
Re-write the first equation as: $y=x+1$
The second equation yields: $x+1=x^2+1$ or, $x^2-x=0$
or, $x(x-1)=0$
or, $x=${$0,1$}
From first equation when $x=0$, we have $y=1$
From first equation when $x=1$, we have $y=2$
Thus, solution set is $(x,y)=${$(0,1),(1,2)$}