Chapter 10 - Section 10.5 - Systems of Nonlinear Equations in Two Variables - Exercise Set - Page 810: 17

{$(0,1),(4,-3)$}

Re-write the first equation as: $y=-x+1$ First equation yields: $(x-1)^2+(-x+1+2)^2=10$ or, $2x^2-8x=0$ or,$2x(x-4)=0$ or, $x=${$0,4$} From first equation when $x=0$, we have $y=1$ From first equation when $x=4$, we have $y=-3$ Thus, solution set is {$(0,1),(4,-3)$}