Answer
$h^{-1}(x) = \frac{x+1.6 }{0.4}$
Work Step by Step
$h(x) = 0.4x - 1.6$
Let $h(x) = y$:
$y = 0.4x - 1.6$.
Switch the variables $x$ and $y$ to find the inverse and solve for $y$:
$x = 0.4y - 1.6$
$x + 1.6 = 0.4y$
$y = \frac{x+1.6 }{0.4}$
$h^{-1}(x) = \frac{x+1.6 }{0.4}$.
