Answer
$f^{-1}(x) = \frac{x-7}{5}$
Work Step by Step
$f(x) = 5x+7$
Let $f(x) = y$:
$y = 5x + 7$
Switch the variables $x$ and $y$ to find the inverse:
$x = 5y + 7$
$x - 7 = 5y$
$y = \frac{x-7}{5}$
$f^{-1}(x) = \frac{x-7}{5}$
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