Answer
$g^{-1}(t) = -\frac{t-8}{4}$
Work Step by Step
$g(t) = -4t + 8$
Let $g(t) = y$:
$y = -4t + 8$
Switch the variables $t$ and $y$ to find the inverse:
$t = -4y + 8$
$t - 8 = -4y$
$y = -\frac{t-8}{4}$
$g^{-1}(t) = -\frac{t-8}{4}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.1 Functions and Their Inverses - 6.1 Exercises - Page 494: 37
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