Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-4 - Cumulative Review - Page 408: 8

Answer

$n=0, -18, 12$

Work Step by Step

We find: $2n^3 + 12n^2 - 432n=0$ $(n)(n + 18)(n - 12)=0$ $n=0, -18, 12$
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