Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-4 - Cumulative Review - Page 408: 17

Answer

for $a=2.1349, b= 2.0781$ for $a=-2.044, b= -11.5982$

Work Step by Step

Substitute $b=3a^2+3a-18$ $3a^2+3a-18=-8a^2+4a+30$ $ 11a^2-a-48=0$ $a=2.1349 , -2.044$ for $a=2.1349, b= 2.0781$ for $a=-2.044, b= -11.5982 $
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