Answer
False
Work Step by Step
The quotient property of logarithms tells us that $log_{b}\frac{x}{y}=log_{b}x-log_{b}y$ (where x, y, and, b are positive real numbers and $b\ne1$).
Therefore, the term on the right side is equivalent to $log_{7}x-log_{7}y= log_{7}(\frac{x}{y})$, which is not equivalent to the term on the left side. This statement is false.
