Answer
${\frac{1}{2}}$
Work Step by Step
If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x\gt0$ and every real number $y$.
Therefore, $log_{7}\sqrt 7=\frac{1}{2}$.
We know this because $7^{\frac{1}{2}}=\sqrt 7$.
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Section 9.6 - Properties of Logarithms - Exercise Set - Page 579: 70
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