Answer
-2
Work Step by Step
We are given that $f(x)=x^{2}-2$, $g(x)=x+1$, and $h(x)=x^{3}-x^{2}$.
We know that $(f\circ g)(x)=f(g(x))$.
Therefore, $(f\circ g)(-1)=f(g(-1))=f(-1+1)=f(0)=0^{2}-2=-2$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Review - Page 596: 9
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
