Answer
$x^{4}-4x^{2}+2$
Work Step by Step
We are given that $f(x)=x^{2}-2$, $g(x)=x+1$, and $h(x)=x^{3}-x^{2}$.
We know that $(f\circ f)(x)=f(f(x))$.
Therefore, $(f\circ f)(x)=f(f(x))=f(x^{2}-2)=(x^{2}-2)^{2}-2$
We know that a binomial of the form $(a-b)^{2}$ will simplify to $a^{2}-2ab+b^{2}$.
Therefore, $(x^{2}-2)^{2}-2=(x^{2\times2}-2(2x^{2})+4)-2=x^{4}-4x^{2}+2$.
