Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Systems of Linear Equations and Problem Solving - Exercise Set - Page 324: 81

Answer

l=12 w=15/2

Work Step by Step

l=2w-3 l*w=90 Substitute (2w-3)(w)=90 2w^2-3w-90=0 Using ac method find two numbers that whose products are -180 and their sum is -3. The two number are -15 and 12 2w^2+12w-15w-90=0 2w(w+6)-15(w+6) (2w-15)(w+6) w+6=0 w=-6 Does not make sense 2w-15=0 2w=15 w=15/2 (l)(15/2)=90 l=90/1/15/2 l=12
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