Answer
The height of the object at $t=0$ is $576$ ft.
The height of the object at $t=2$ is $672$ ft.
The height of the object at $t=4$ is $640$ ft.
The height of the object at $t=6$ is $480$ ft.
Work Step by Step
The given equation is $h(t)=-16t^{2}+80t+576$.
To find the height of the object when $t=0$, substitute $0$ in for $t$.
$h(0)=-16(0)^{2}+80(0)+576$
Evaluate: $-16(0)^{2}+80(0)+576=576$
Therefore, the height of the object when $t=0$ is $576$ ft.
To find the height of the object when $t=2$, substitute $2$ in for $t$.
$h(2)=-16(2)^{2}+80(2)+576$
Evaluate: $-16(2)^{2}+80(2)+576=672$.
Therefore, the height of the object when $t=2$ is $672$ ft.
To find the height of the object when $t=4$, substitute $4$ in for $t$.
$h(4)=-16(4)^{2}+80(4)+576$
Evaluate: $-16(4)^{2}+80(4)+576=640$.
Therefore, the height of the object when $t=4$ is $640$ ft.
To find the height of the object when $t=6$, substitute $6$ in for $t$.
$h(6)=-16(6)^{2}+80(6)+576$
Evaluate: $-16(6)^{2}+80(6)+576=480$.
Therefore, the height of the object when $t=6$ is $480$ ft.
