Answer
$V(x)=x(x+4)(x-2)$
Work Step by Step
Factor out the GCF of $x$ to have:
$\\V(x)=x(x^2+2x-8)$
$\\\\$The factors of $-8$ whose sum is equal to the middle term (2) are 4 and 2.
Thus, the factored form of the trinomial is $(x+4)(x-2)$.
Therefore, the completely factored form of the given expression is:
$\\V(x)=x(x+4)(x-2)$
