Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 304: 93

Answer

$x^3-8$

Work Step by Step

Using $ (a\pm b)(a^2\mp ab+b^2)=a^3\pm b^3 $, then, \begin{align*} (x-2)(x^2+2x+4) \Rightarrow x(x^2)+(-2)(4) \\= x^3-8 .\end{align*}
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