Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 332: 156

Answer

$$x=13$$ $$x=-2$$

Work Step by Step

We have $$x(x-11)=26$$ Expanding the equation and sending all the terms to the left side of the equation $$x^2-11x-26=0$$ Factorizing $$(x-13)(x+2)=0$$ Solving each parenthesis 1) $$x-13=0$$ $$x=13$$ 2)$$x+2=0$$ $$x=-2$$
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