Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 332: 146

Answer

$$49a^2b^2-7ab+\frac{1}{4}$$

Work Step by Step

We have $$(7ab-\frac{1}{2})^2$$ Squaring $$49a^2b^2-7ab+\frac{1}{4}$$
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