Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 332: 152

Answer

$$(4x+3)^2(y-20)(y+1)$$

Work Step by Step

We have $$y^2(4x+3)^2-19y(4x+3)^2-20(4x+3)^2$$ Factorizing $$(4x+3)^2(y^2-19y-20)$$ $$(4x+3)^2(y-20)(y+1)$$
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