Answer
$9x^{2a}-16$
Work Step by Step
Using $(a+b)(a-b)=a^2-b^2$ of the product of the difference of two squares, then,
\begin{array}{l}
(3x^a-4)(3x^a+4)
\\=
(3x^a)^2-(4)^2
\\=
9x^{2a}-16
.\end{array}
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