Answer
$-12a^{2}b^{5}-28a^{2}b^{3}-4ab^{2}$
Work Step by Step
$-4ab^{2}(3ab^{3}+7ab+1)$
Distribute the $-4ab^{2}$.
$-4ab^{2}(3ab^{3})-4ab^{2}(7ab)-4ab^{2}(1)$
Simplify.
$-12a^{2}b^{5}-28a^{2}b^{3}-4ab^{2}$
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