Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 330: 65

Answer

$36x^{3}-11x^{2}-8x-3$

Work Step by Step

$(9x^{2}+4x+1)(4x-3)$ Distribute: first the $4x$ and then the $(-3)$ $(4x)(9x^{2})+(4x)(4x)+(4x)(1)+(-3)(9x^{2})+(-3)(4x)+(-3)(1)$ Simplify $-36x^{3}+16x^{2}+4x-27x^{2}-12x-3$ Combine like terms $36x^{3}-11x^{2}-8x-3$
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