Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Test - Page 633: 8

Answer

Refer to the graph below.

Work Step by Step

RECALL: The graph of the equation $\dfrac{y^2}{a^2}-\dfrac{x^2}{b^2}=1$ is a vertical hyperbola whose center is at $(0, 0)$. The given equation can be written and is equivalent to: $\dfrac{y^2}{1^2}-\dfrac{x^2}{1^2}=1$ Thus, its graph is a vertical hyperbola. To graph this hyperbola, perform the following steps: (1) Plot the center $(0, 0)$ and the vertices $(0, 1)$ and $(0, -1)$. (2) Sketch the asymptotes $=x$ and $y=-x$ using broken lines. These lines serve as guide and are not part of the hyperbola itself. (3) Graph the hyperbola using the asymptotes as guide. Refer to the graph above.
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