Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Test - Page 633: 4

Answer

Refer to the graph below.

Work Step by Step

Factor the trinomial to obtain: $y=x^2-8x+16 \\y=(x-4)(x-4) \\y=(x-4)^2$ Recall: The graph of $y=(x-h)^2+k$ is a parabola that opens upward whose vertex is at $(h, k)$. The equation above can be written as $y=(x-4)^2+0$. Thus, its graph sis a parabola whose vertex is at $(4, 0)$. To graph this equation, perform the following steps: (1) Create a table of values by assigning $x=2, 3, 4, 5, 6$ then solving for the corresponding value of $y$ for each one. Refer to the table below. (2) Plot each point from the table then connect the points using a smooth curve. Refer to the graph in the answer part above.
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