Answer
$(6,12),(1,2)$
Work Step by Step
$y=x^{2}-5x+6$ Equation $(1)$
$y=2x$ Equation $(2)$
From Equation $(1)$ and Equation $(2)$
$x^{2}-5x+6 = 2x$
$x^{2}-5x+6-2x=0$
$x^{2}-7x+6=0$
By factoring,
$(x-6)(x-1)=0$
$x=6$ or $x=1$
Substitute $x$ values in Equation $(2)$ to get corresponding $y$ values.
Let $x=6$
$y=2x$
$y=2(6)$
$y=12$
Let $x=1$
$y=2x$
$y=2(1)$
$y=2$
$(6,12),(1,2)$ satisfy the given equations.
Solutions are $(6,12),(1,2)$
