Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 633: 8d

Answer

$\dfrac{3a^{4}}{2}$

Work Step by Step

Using laws of exponents, the expression $ \dfrac{18a^{12}b^{6}}{12a^8b^6} $ simplifies to \begin{array}{l} \dfrac{3a^{12-8}b^{6-6}}{2} \\\\= \dfrac{3a^{4}}{2} .\end{array}
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