Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 633: 7c

Answer

$\dfrac{9p^{8}}{q^{10}}$

Work Step by Step

Using laws of exponents, the expression $ \left(\dfrac{3p^4}{q^5}\right)^2 $ simplifies to \begin{array}{l} \dfrac{3^2p^{4(2)}}{q^{5(2)}} \\\\= \dfrac{9p^{8}}{q^{10}} .\end{array}
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