Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 633: 8a

Answer

$1024$

Work Step by Step

Using laws of exponents, the expression $ \dfrac{4^8}{4^3} $ simplifies to \begin{array}{l} 4^{8-3} \\\\= 4^{5} \\\\= 1024 .\end{array}
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