Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 86: 37

Answer

$z=-\dfrac{1}{20}$

Work Step by Step

Adding $ \dfrac{1}{5} $ to both sides of the given equation, $ -\dfrac{1}{5}+z=-\dfrac{1}{4} $, then, \begin{array}{l} -\dfrac{1}{5}+z+\dfrac{1}{5}=-\dfrac{1}{4}+\dfrac{1}{5} \\\\ z=-\dfrac{1}{4}+\dfrac{1}{5} \\\\ z=-\dfrac{5}{20}+\dfrac{4}{20} \\\\ z=-\dfrac{1}{20} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.