Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 86: 33

$x=-\dfrac{1}{10}$

Adding $ \dfrac{3}{5} $ to both sides of the given equation, $ x-\dfrac{3}{5}=-\dfrac{7}{10} $, then, \begin{array}{l} x-\dfrac{3}{5}+\dfrac{3}{5}=-\dfrac{7}{10}+\dfrac{3}{5} \\\\ x=-\dfrac{7}{10}+\dfrac{6}{10} \\\\ x=-\dfrac{1}{10} .\end{array}