Chapter 2 - Equations, Inequalities, and Problem Solving - 2.1 Solving Equations - 2.1 Exercise Set - Page 86: 34

$x=-\dfrac{1}{6}$

Adding $ \dfrac{2}{3} $ to both sides of the given equation, $ x-\dfrac{2}{3}=-\dfrac{5}{6} $, then, \begin{array}{l} x-\dfrac{2}{3}+\dfrac{2}{3}=-\dfrac{5}{6}+\dfrac{2}{3} \\\\ x=-\dfrac{5}{6}+\dfrac{4}{6} \\\\ x=-\dfrac{1}{6} .\end{array}