Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 13 - Conic Sections - 13.2 Conic Sections: Ellipses - 13.2 Exercise Set - Page 862: 50

Answer

$SF=2.134\times10^8\text{ mi}$

Work Step by Step

It's easier to solve if there is a picture. In our picture the maximum distance of Mars from the sun is $SB=2.48\times10^8\text{ mi}$. Its minimum distance is $SA=3.46\times10^7\text{ mi}$. We have to find $SF$. $SF=SB-FB.$ But from the properties of the ellipse, we know that $FB=SA$. Hence $SF=SB-SA=2.48\times10^8-3.46\times10^7 (\text{mi})$ $SF=21.34\times10^7\text{ mi}=2.134\times10^8\text{ mi}$
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