Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 13 - Conic Sections - 13.2 Conic Sections: Ellipses - 13.2 Exercise Set - Page 862: 41

Answer

$x_1=\sqrt{11}$ $x_2=-\sqrt{11}$

Work Step by Step

We have to solve $x^2=11$. Taking the square root of the left and right sides we get two solutions. $$x_1=\sqrt{11}$$ $$x_2=-\sqrt{11}$$
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