Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.7 Applications of Exponential Functions and Logarithmic Functions - 12.7 Exercise Set - Page 834: 13

Answer

The pH value of fresh-brewed coffee is about $4.9$.

Work Step by Step

First, note that the hydrogen ion concentration of fresh brewed coffee is about $1.3\times {{10}^{-5}}$moles per liter. Therefore, $\left[ {{\text{H}}^{\text{+}}} \right]=1.3\times {{10}^{-5}}$. Substitute it in the formula $\text{pH}=-\log \left[ {{\text{H}}^{\text{+}}} \right]$as follows: $\begin{align} & \text{pH}=-\log \left[ {{\text{H}}^{\text{+}}} \right] \\ & \text{pH}=-\log \left[ 1.3\times {{10}^{-5}} \right] \\ \end{align}$ Therefore, $\begin{align} & \text{pH}=-\log \left[ 1.3\times {{10}^{-5}} \right] \\ & \text{pH}\approx -\left( -4.8860 \right) \\ & \text{pH}\approx 4.8860 \end{align}$
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