Answer
True.
Work Step by Step
Apply the change of base formula, $\displaystyle \log_{b}M=\frac{\log_{a}M}{\log_{a}b}.$
$\log_{2}9 =\displaystyle \frac{\log_{e}9}{\log_{e}2}=\frac{\ln 9}{\ln 2}$
so the statement is true.
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 12 - Exponential Functions and Logarithmic Functions - 12.5 Common Logarithms and Natural Logarithms - 12.5 Exercise Set - Page 818: 6
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