Answer
$a.\quad 40,42,46,50$
$ b.\quad$Yes, $\quad f^{-1}(x)=x-32$
$c.\quad 8,10,14,18$
Work Step by Step
$ a.\quad$
$f(8)=8+32=40$
$f(10)=10+32=42$
$f(14)=14+32=46$
$f(18)=18+32=50$
$ b.\quad$
$f(x)=x+32$
is a linear function, not constant, so its graph is an oblique line that passes the horizontal line test.
It is one-to-one and has an inverse.
To find a formula for the inverse,
1. Replace $f(x)$ with $y.$
$y=x+32$
2. Interchange $x$ and $y$. (This gives the inverse function.)
$x=y+32$
3. Solve for $y.$
$x-32=y$
4. Replace $y$ with $f^{-1}(x)$ . (This is inverse function notation.)
$f^{-1}(x)=x-32$
$ c.\quad$
$f^{-1}(40)=40-32=8$
$f^{-1}(42)=42-32=10$
$f^{-1}(46)=46-32=14$
$f^{-1}(50)= 50-32=18$
