Chapter 9 - Roots and Radicals - 9.5 - Solving Radical Equations - Problem Set 9.5 - Page 424: 5

No solution

Recall, in order to cancel out a square root, we square both sides of the equation. Thus, we square both sides of the equation to obtain that 3x=36. We divide both sides of the equation by 3 to isolate x and obtain: x=12. We now must check our solution: $\sqrt{3 \times 12} = -6 \\\\\ \sqrt {36}=-6 \\\\ 6 = -6$ This is not true, so there is no solution.