Answer
$\frac{x+7}{(2x-1)(3x+1)}$
Work Step by Step
By inspection, we see that the LCM of the denominators is $(2x-1)(3x+1)$. Therefore, we create a common denominator using this LCM and obtain:
$\frac{3}{2x-1}-\frac{4}{3x+1}$
=$\frac{3(3x+1)-4(2x-1)}{(2x-1)(3x+1)}$
=$\frac{9x+3-8x+4)}{(2x-1)(3x+1)}$
=$\frac{x+7}{(2x-1)(3x+1)}$
