Answer
$\frac{-4}{x(3x-2)}$
Work Step by Step
By inspection, we see that the LCM of the denominators is $x(3x-2)$. Therefore, we create a common denominator using this LCM and obtain:
$\frac{2}{x}-\frac{6}{3x-2}$
=$\frac{2(3x-2)-6(x)}{x(3x-2)}$
=$\frac{6x-6x-4}{x(3x-2)}$
=$\frac{-4}{x(3x-2)}$