Answer
$\frac{10x-35}{x(x-5)}$
Work Step by Step
By inspection, we see that the LCM of the denominators is $x(x-5)$. Therefore, we create a common denominator using this LCM and obtain:
$\frac{3}{x-5}+\frac{7}{x}$
=$\frac{x(3)+7(x-5)}{x(x-5)}$
=$\frac{3x+7x-35}{x(x-5)}$
=$\frac{10x-35}{x(x-5)}$
