Answer
$\dfrac{4xy}{7}$
Work Step by Step
Cancelling the common factor in the numerator and the denominator, the given expression, $
\dfrac{8x^2y}{14x}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{\cancel{2x}\cdot4xy}{\cancel{2x}\cdot7}
\\\\=
\dfrac{4xy}{7}
.\end{array}
