Answer
$-1$
Work Step by Step
Recall, in order to solve problems involving order of operations, we use the PEMDAS rule.
First Priority: P - parentheses and other grouping symbols (including fraction bars)
Second Priority: E - exponents
Third Priority: M/D - Multiplication or division, whichever comes first from the left to the right
Fourth Priority: A/S - Addition or subtraction, whichever comes first from the left to the right
We follow order of operations to obtain that the expression, $
\dfrac{4(2)^3}{16}-\dfrac{2(3)^2}{6}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{4(2)(2)(2)}{16}-\dfrac{2(3)(3)}{6}
\\\\=
\dfrac{\cancel{2}\cdot2(\cancel{2})(\cancel{2})(\cancel{2})}{\cancel{2}(\cancel{2})(\cancel{2})(\cancel{2})}-\dfrac{\cancel{2}(3)(\cancel{3})}{\cancel{2}(\cancel{3})}
\\\\=
2-3
\\\\=
-1
.\end{array}
