Answer
{$\frac{1}{2}$}
Work Step by Step
Using the rules for the factoring of trinomials, we obtain:
$4x^{2}-4x+1=0$
$4x^{2}-2x-2x+1=0$
$2x(2x-1)-1(2x-1)=0$
$(2x-1)(2x-1)=0$
$(2x-1)=0$ and $(2x-1)=0$
$x=\frac{1}{2}$ and $x=\frac{1}{2}$
Therefore, the solution set is {$\frac{1}{2}$}.
