Answer
{$\frac{2}{7},\frac{1}{3}$}
Work Step by Step
Using the rules for the factoring of trinomials, we obtain:
$21x^{2}-13x+2=0$
$21x^{2}-6x-7x+2=0$
$3x(7x-2)-1(7x-2)=0$
$(7x-2)(3x-1)=0$
$(7x-2)=0$ and $(3x-1)=0$
$7x=2$ and $3x=1$
$x=\frac{2}{7}$ and $x=\frac{1}{3}$
Therefore, the solution set is {$\frac{2}{7},\frac{1}{3}$}.
