Answer
{$-6,-1$}
Work Step by Step
Using Property 10.1, which says that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain:
Step 1: $(2x+7)^{2}=25$
Step 2: $2x+7=\pm \sqrt {25}$
Step 3: $2x+7=\pm 5$
Step 4: $2x+7=5$ or $2x+7=-5$
Step 5: $2x=5-7$ or $2x=-5-7$
Step 6: $2x=-2$ or $2x=-12$
Step 7: $x=-1$ or $x=-6$
The solution set is {$-6,-1$}.
