Answer
The solution is $(1,-5)$.
Work Step by Step
The given system is
$y=x^2-2x-4$ ...... (1)
$y=-5$ ...... (2)
Substitute $-5$ for $y$ in equation (1).
$\Rightarrow -5=x^2-2x-4$
Add $5$ to each side.
$\Rightarrow -5+5=x^2-2x-4+5$
Simplify.
$\Rightarrow 0=x^2-2x+1$
Write the right side terms as square of the polynomial.
$\Rightarrow 0=(x-1)^2$
Take square root on each side.
$\Rightarrow 0=x-1$
Solve for $x$.
$\Rightarrow x=1$
Hence, the solution is $(1,-5)$.
