Answer
$x=1$.
Work Step by Step
$-5x^{2}+10x=5$
Subtracting $5$ from both sides, we get
$-5x^{2}+10x-5=0$
Comparing $-5x^{2}+10x-5=0$ with $ax^{2}+bx+c=0$, we see that $a=-5, b=10$ and $c=-5$.
Using the quadratic formula, we have
$x=\frac{-b\pm \sqrt {b^{2}-4ac}}{2a}=\frac{-10\pm\sqrt {(10)^{2}-4(-5)(-5)}}{2(-5)}$
$=\frac{-10}{-10}=1$
The solution of the given equation is $x=1$.
