Answer
$x\approx3.45$ and $x\approx-1.45$
Work Step by Step
$2x^{2}-4x=10$.
Dividing both sides by $2$, we have
$x^{2}-2x=5$
Comparing the above equation with $x^{2}+bx=d$, we see that $b=-2$.
To complete the square, we add $(\frac{b}{2})^{2}=(\frac{-2}{2})^{2}=1$ to both sides of the equation.
Then $x^{2}-2x+1=6$
Or $(x-1)^{2}=6$
Taking square root on both sides, we get
$x-1=\pm\sqrt {6}$
Adding $1$ to both sides of the equation, we have
$x=1\pm\sqrt {6}$
The solutions of the equation are $x=1+\sqrt {6}\approx3.45$ and $x=1-\sqrt 6\approx-1.45$
